Explain why x-4 2 -9 has no real solutions

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August undefined, 2024

WebAlgebra. Equation Solver. Step 1: Enter the Equation you want to solve into the editor. The equation calculator allows you to take a simple or complex equation and solve by best … WebNov 20, 2015 · Since 0^2+1=0+1=1(not equal to 0) ; then x€real number is not a solution of x^2+1=0 therefore x^2+1=0 has a non-zero solution. Now we have to extablish the …

How to tell if an equation has no real solution - Quora

WebExpert solutions Question Explain why the following polynomial equation has no real solutions: 0=5 x^ {8}+10 x^ {6}+7 x^ {4}+18 x^ {2}+132 0 = 5x8 + 10x6 +7x4 +18x2 + … WebVirtual Nerd's patent-pending tutorial system provides in-context information, hints, and links to supporting tutorials, synchronized with videos, each 3 to 7 minutes long. In this non-linear system, users are free to take whatever path through the material best serves their needs. These unique features make Virtual Nerd a viable alternative to private tutoring. peterborough manager odds

Solve Using the Square Root Property (x-4)^2=9 Mathway

WebAug 8, 2015 · Prove that the trigonometric equation $$\frac{\sin^3 x}{1-\sin x}+\frac{\cos^3 x}{1-\cos x}=-1$$ has no solution. I tried applying $T2's$ lemma to contradict but could … WebSep 22, 2024 · If it is negative, then the quadratic equation does not have any real solutions. If the quadratic equation is given as a x 2 + b x + c = 0, then we can write the standard form of the quadratic formula as: x = − b ± b 2 − 4 a c 2 a. In this formula, the term b 2 − 4 a c is called discriminant, denoting it as “ D ”. peterborough – man city

Prove that $x^2 = - 1$ has no solution in $\\mathbb{Z}$

WebTranscribed Image Text: Part 1: Show how to solve the equation 2x +1– 4 = -1. Part 2: Explain why /2x +1+4=-1 has no real solution. WebSolve for x x-4 =2. Step 1. ... The complete solution is the result of both the positive and negative portions of the solution. Tap for more steps... Step 2.1. First, use the positive … starfit fitness \u0026 yogaWebExplain why the quadratic equation $$ x^2+4=0 $$ has no Quizlet Expert solutions Question Explain why the quadratic equation x^2+4=0 x2 + 4 = 0 has no real solutions … peterborough manager history

"WebMar 14, 2024 · Taking into account the discriminant and quadratic formula: As Δ> 0 the function has two real roots or solutions. The solutions are x1= 10 and x2= -2. Zeros or … " - Explain why x-4 2 -9 has no real solutions

Explain why x-4 2 -9 has no real solutions

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Web"Imaginary solutions", "double roots", "conjugate pairs" and all that stuff sounds mysterious, but it only ends up that way because you're trying to find a relationship between a y value of zero, and x. The coordinate for a real number solution would be (x,0), so if there is no x intercept it's game over. Web x+4 =−1 The absolute value cannot be negative. Therefore, there is no solution. Because it always says when you take the absolute symbols off, you get a negative number as well as a positive number the solutions I came up with were -3 and -5. All throughout the practice there are solutions with fractions where both fractions are negative.

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WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Webx 2 + 4x + 4 = x 2 + 4x – 5 [FOIL the left side] 4 = -5 [subtract x 2 + 4x from both sides] Since 4 = -5 is always false, we know that this equation has no solution. No matter which value …

Web2. Perhaps the question should really be: The polynomial is given , show that the equation has no real solution. – projectilemotion. Jul 10, 2024 at 18:34. 1. You can prove that is never zero if you can show that it has a global minimum which is a positive number. Web$$ \begin{cases} x_1+hx_2=2\\ 4x_1+8x_2=k\\ \end{cases} $$ Has (a) no solution, (b) a unique solution, and (c) many solutions. First i made an augmented matrix, then performed row reduction:

WebWe know you can’t take the square root of a negative number without using imaginary numbers, so that tells us there’s no real solutions to this equation. This means that at … WebThe solutions to Power Equations and the solutions to Radical Equations are different things. For example, x^2 = 4 has two solutions: x = ±2, while x = √4 has only one solution: x = 2, and x = -√4 also has one solution: x = -2. We define the square root as a function, so it must have only one output for each input.

WebExplain why (x-4)^(2)=-9 has no real solutions. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.

WebFeb 25, 2012 · For some equations that do not have a real solution, for example, x^2 + 1 = 0, there are solutions if the domain is extended to the complex field. x + 2 = x - 2 has no... peterborough magazineWebSep 8, 2024 · Explanation: No x-intercept means that it does not cross the x-axis. Thus two solutions is definitely ruled out. However, if you DO NOT INCLUDE a point of coincidence (Vertex coincides with the x-axis) in the phrase "does not have an x-intercept". Then there could be a single value solution if you equate the quadratic to 0. peterborough man cityWebDec 23, 2024 · 3 Answers. If a > 0 then f ( x) = a x 2 + b x + c > x for sufficiently large x. And as f ( x) = x has no real root then f ( x) > x for all x (otherwise there will be a real root). Hence f ( f ( x)) > f ( x) > x for all x. So, f ( f ( x)) = x has no real root. Similarly for a < 0. ( + if a > 0 and − if a < 0). star fix reviewsWebThis trick is based on simplifying and as soon as you see the same coefficients of the variable on both sides and any different numbers on the two sides, you know that … peterborough mapsWebAnswer (1 of 6): By definition, any equation will have some functional expression on the right and one on the left. Something like this: f(x,y,z,…) = g(x,y,z,…) At this point, the most basic test you can do is to check if their ranges overlap … peterborough mappingWebWe assume that there is more than one real solution for this equation, namely f ( a) = 0 = f ( b). If there exists more than one real solution for f ( x) = 0 then f ( a) = 0 = f ( b) a = b, and thus there is only one real solution to the equation, as desired. peterborough mall storesWebMar 10, 2024 · Given, (x – 4)² = -9. The LHS of the equation is either positive or zero. But, the RHS of the equation is a negative value. Therefore, RHS and LHS can never be equal. Hence, the equation (x – 4)² = -9 has no real roots. To learn more about quadratic … starfix splint